Anderson's game of 24

Let's take out the prime factors of the given number $24$ , which are $2 \times 2 \times 2 \times 3$ . These can be arranged in the forms of pairs-

$2 \times 12$ , $3 \times 8$ and $4 \times 6$ .

But we have to choose pairs which have numbers between $0$ and $10$ .

Thus, we get only two pairs- $3 \times 8$ and $4 \times 6$ .

Since this question asks for the number of ordered pairs, we can form two more pairs from these two pairs, giving us a total of $\fbox{4}$ pairs.

We find the number of ordered pairs of factors from 0 to 10. We find these: $(3,8)$ $(4,6)$ $(6,4)$ $(8,3)$ The answer is $\boxed{4}$ .

First, reach the factor of $24$ , that is; $2,3,4,6,8,12,24$

Because the integers that thought by Petr is between $0$ to $10$ , and the product of them is $24$ .

So the number, and its possible ''structure'' is: $3,8$ $4,6$ $6,4$ $8,3$

There is $4$ possible

There are 4 combinations of 2 numbers whose product is 24 from 0 to 10 , ie. (3,8) , (8,3), (4,6) and (6,4).

It can be 3x8, 8x3, 6x4 or 4x6

Since it is given that integers are from 0-10 then possible product of integers are 8 3 and 6 4.But distinct ordered possible pair of integers are - (3),(4),(6),(8) so correct answer is 4 if you count it.Here 83 and 64 means product of 8,3 and 6,4

24= 8 * 3 = 6 * 4

( 8 , 3 ) , ( 3 , 8 ) , ( 6 , 4 ) , ( 4 , 6 )

(3,8)(8,3)(4,6)(6,4)

The factors of 24 are 1,2,3,4,6,8,12,24. Now, we can see that the ordered pairs satisfying this are (1,24),(24,1),(2,12),(12,2),(3,8),(8,3),(4,6) and (6,4).

But, it is also said that for the ordered pair (a,b), we have a and b can range from 0 to 10. So, the ordered pairs (1,24),(24,1),(2,12) and (12,2) does not satisfy this. So, these pairs does not belong in the solution set.

Only 4 ordered pairs, i.e, (3,8),(8,3),(6,4) and (4,6) belong in the solution set, so no. of required ordered pairs $=\boxed{4}$

integers r frm 0 to 10.... so 24 is our product\ possible factors are 8 3 or 4 6... then (4,6),(8,3)...total 4 integers! Ans= 4

The answer is =(3 x 8),(4 x 6) = (8 x 3),(6 x 4) = These are the 4 pairs whose product is 24.{between 0 to 10}

In between 0 and 10, there is only possible to take 8,3 and 4.6 pairs for the product 24. If we interchange we get 4 pairs. i.e., (8,3), (4,6), (3,8), (6,4).

Different factors of 24 are; (24,1) - (12,2) - (8,3) - (6,4) = 4 unlike ordered pairs.