Andrew's function - 1

Putting $x=1,2$ in $A(x)=px+q$ , we have $A(1)=p+q=1729$ and $A(2)=2p+q=2016$ and then subtracting the first equation from second , we have $p=287$ and substituting $p=287$ in any one of them , we get $q=1442$ . Thus $p-q=287-1442=\boxed{-1155}$ .