Find (a,b) such that the circles cut orthogonally.
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For two circles, x 2 + y 2 + 2 g 1 x + 2 f 1 y + c 1 = 0 and x 2 + y 2 + 2 g 2 x + 2 f 2 y + c 2 = 0 , to be orthogonal, the following condition must be satisfied.
2 g 1 g 2 + 2 f 1 f 2 = c 1 + c 2
On applying the above condition, we get a 2 + b 2 = 0 .
this implies a = b = 0
But these values of a and b make the circles concentric. Hence there is no actual intersection of the circles possible which may make them orthogonal.