Angle between the circles.

Geometry Level 4

Find (a,b) such that the circles cut orthogonally.

None Of these (0,1) (1,0) (0,0)

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1 solution

For two circles, x 2 + y 2 + 2 g 1 x + 2 f 1 y + c 1 = 0 x^2 + y^2 + 2g_1x + 2f_1y + c_1 = 0 and x 2 + y 2 + 2 g 2 x + 2 f 2 y + c 2 = 0 x^2 + y^2 + 2g_2x + 2f_2y + c_2 = 0 , to be orthogonal, the following condition must be satisfied.

2 g 1 g 2 + 2 f 1 f 2 = c 1 + c 2 2g_1g_2 + 2f_1f_2 = c_1 + c_2

On applying the above condition, we get a 2 + b 2 = 0 a^2 + b^2 = 0 .

this implies a = b = 0 a=b=0

But these values of a a and b b make the circles concentric. Hence there is no actual intersection of the circles possible which may make them orthogonal.

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