Angle made by water surface!

Classical Mechanics Level 2

A cylindrical vessel filled with water is released on an inclined surface of angle θ \theta as shown in figure. The friction coefficient of surface with vessel is ( μ < tan ⁡ θ \mu < \tan \theta ). Then the constant angle made by the surface of water with the incline will be:

cot ⁡ − 1 μ \cot^{-1} \mu tan ⁡ − 1 μ \tan^{-1} \mu θ + tan ⁡ − 1 μ \theta +\tan^{-1} \mu θ − tan ⁡ − 1 μ \theta -\tan^{-1} \mu None of these choices

Nishant Rai by Nishant Rai , 25, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Nishant Rai
May 26, 2015

12 Helpful 5 Interesting 2 Brilliant 7 Confused

Had earlier solved same problem in cengage. just marked the option

Pranjal Prashant - 5 years, 8 months ago

Solution is not clear.please provide clear solution

Manish Tomar - 5 years, 5 months ago

If Mg sin(thita) is larger then mue cos(thita) then these can not balance

Manish Tomar - 5 years, 5 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...