Angle of dip?-2

Electricity and Magnetism Level pending

At certain place on earth B H = 1 3 B V . B_H=\frac{1}{\sqrt3}B_V. . The dip angle at that place (in degrees) is:


The answer is 60.

Ayush G Rai by Ayush G Rai , 20, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

Ayush G Rai
Jun 13, 2016

Let the angle of dip be θ . \theta.
t a n θ = B V B H tan\theta=\frac{B_V}{B_H}
t a n θ = B V 1 3 B V tan\theta=\frac{B_V}{\frac{1}{\sqrt3}B_V}
t a n θ = 3 tan\theta=\sqrt3
θ = 6 0 ∘ . \theta=\boxed {60^\circ}.


2 Helpful 0 Interesting 0 Brilliant 0 Confused

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...