Angles in a Triangle

Let the third angle (angle CAB) be 'x'.

By angle sum property of a triangle, we have,

12 + 34 + x = 180

46 + x = 180

So x = 134. Hence angle CAB will be 134 degrees.

180 degrees in a triangle. 12+34=46 180-46=134

A soma dos ângulos internos de um triângulo é sempre 180º, portanto, como dois de seus ângulos já estão dados, temos facilmente que o terceiro é : 180 - 12 - 34 = 134º

∠ABC=12∘, ∠BCA=34∘

Sum of angles in a triangle is 180∘ Which implies, ∠ABC+∠BCA+∠CAB=180∘

12∘+34∘+∠CAB=180∘

∠CAB =180∘-12∘-34∘

                    =180∘-46∘

∠CAB = 134∘

12+34=46-180=134

Sum of all angles of a triangle is 180 degrees ,

angle ABC +angle BCA +angle CAB =180 degrees, 12+34+angle CAB =180, angle CAB=180-46 degrees, angle CAB=134

180 - 34 - 12 =

∠ABC+∠BCA+∠CBA=180 {ANGLE SUM PROPERTY] 12 + 34 +∠CBA=180 46 +∠CBA=180 ∠CBA=180-46 {TRANSPOSING 46} ∠CBA=134

measure of interior angles of a triangle = 180∘

∠ABC + ∠BCA + ∠CAB = 180

12 + 34 + ∠CAB = 180

∠CAB = 180 - 46

∠CAB = 134∘

se a soma dos ângulos dos lados é 180, 12+34=46 ... 180-46= 134

We know that,

The sum of all three angles of a triangle is 180∘

Hence, in triangle $△ABC$ ,

$∠ABC+∠BCA+∠CAB = 180∘ \Longrightarrow 12∘+34∘+∠CAB=180∘$

$\Longrightarrow ∠CAB=180∘-12∘-34∘=134∘$

Hence, the answer is $\fbox {134}$