Angles in Stars

Geometry Level 4

A fascinating property of the p p -pointed star, { p / q } \{p/q\} , is that its sum of angles at the "points" does not depend on the polygon chosen to construct it. It only depends on the p p and q q chosen.

What is the the sum of angles at the "points" of the 201-pointed star, { 201 / 7 } \{201/7\} , in degrees?

Note: { p / q } \{p/q\} denotes a p p -pointed star formed by joining every q th q^{\text{th}} vertex on a convex p p -gon.


The answer is 33660.

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1 solution

Marta Reece
Apr 28, 2017

The formula for the sum of the angles is 180 p 360 q 180p-360q .

The reasoning behind it:

Every vertex contributes 18 0 180^\circ minus the external angle at that vertex.

The sum of all external angles is equal to the number of times the self-intersecting star polynomial goes around the outside.

This in turn is equal to q q , because by taking, in our case, every 7th vertex, we have to go around another six times to get all those skipped, making a total of 7 trips around.

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