Angles problem

Geometry Level 3

In a triangle Δ A B C \Delta ABC , 2 sin B cos C = 1 2 \sin B\cos C= 1 and the value of tan A \tan A is finite.

Which of its angles can be a right angle?

None of them C C B B A A

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1 solution

Chew-Seong Cheong
Jan 31, 2017

Since tan A \tan A is finite; A 9 0 \implies A \ne 90^\circ . Either B B or C C is a right angles. If C = 9 0 C=90^\circ , 2 sin B cos 9 0 = 0 1 2\sin B \cos 90^\circ = 0 \ne 1 , C 9 0 \implies C \ne 90^\circ . When B = 9 0 B=90^\circ , 2 sin 9 0 cos C = 2 cos C = 1 2 \sin 90^\circ \cos C = 2 \cos C = 1 , cos C = 1 2 \implies \cos C = \frac 12 , C = 6 0 \implies C = 60^\circ and A = 3 0 A = 30^\circ ; and tan A = tan 3 0 \tan A = \tan 30^\circ is finite. Therefore B \boxed{B} is a right angle.

Though I got this correct; but I want to know whether all triangles satisfying these conditions will have angle B = 90 degrees? If no, then shouldnt the "none of these" option be considered too?

Yatin Khanna - 4 years, 4 months ago

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You're right, not all triangles satisfying the given conditions will have B = 9 0 \angle B = 90^{\circ} , so I edited the question to "Which of the angles can be a right angle?", as only B \angle B can be a right angle.

Brian Charlesworth - 4 years, 4 months ago

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