angular acceleration

A particle travels in circular path of radius 20 cm at a speed that is uniformly increasing.
if the speed changes from 5m/s to 6m/s in 2 sec. find the angular acceleration??


The answer is 2.5.

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2 solutions

We know, a T = v v 0 t = 6 5 2 = 0.5 m / s 2 \displaystyle a_{T} = \frac{v - v_{0}}{t} = \frac{6-5}{2} = 0.5 m/s^{2}

Hence, α = a T r = 0.5 1 5 = 2.5 m / s 2 \alpha = \frac{a_{T}}{r} = \frac{0.5}{\frac{1}{5}} = \boxed{2.5 m/s^{2}}

Venture Hi
Sep 18, 2014

Angular acceleration=Tangential acceleration/radius= [(6-5)ms^2/2sec]/20cm = (1/2)/(20/100)= 2.5 rad/sec^2

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