Angular velocity of rod

Classical Mechanics Level 3

A uniform rod of length L L and mass M M lies on a frictionless horizontal table. It is free to move in any way on the table. A small body of mass m m moving with velocity u u collides inelastically with the rod. Find the angular velocity of the rod about the center of mass.

ω = 6 m L ( m + 4 M ) \omega = \frac{6m}{L(m+4M)} ω = 6 M u L ( 4 m + M ) \omega = \frac{6Mu}{L(4m+M)} ω = 3 m u L ( 2 m + M ) \omega = \frac{3mu}{L(2m+M)} ω = 6 m u L ( 4 m + M ) \omega = \frac{6mu}{L(4m+M)}

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Srinivasa Satti by Srinivasa Satti

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