Animals
Probability
Level
2
A veterinarian surveys 26 of his patrons. He discovers that 14 have dogs, 10 have cats, and 5 have fish. Four have dogs and cats, 3 have dogs and fish, and one has a cat and fish. If no one has all three kinds of pets, how many patrons have none of these pets?
The answer is 5.
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Total patrons= 26
Having dog = 14
Having cat = 10
Having fish = 5
Having dog+cat = 4
Having dog+fish = 3
Having cat+fish = 1
Thus, having a least 1 pet = (14+10+5)-(3+4+1)
= 21
Means, patrons having no pet = 26-21 = 5