Another 0=1 Proof

Step 2 says if value of 2 equations are equal their ratio is equal to 1, but that applies to non-zero values of the equations. Also in step 2 by dividing the 2 equations you are considering that

$\frac {0}{0} = 1$

Which is totally absurd or wrong, as

$\frac {0}{0}$

is indeterminate.

The first mistake is in $\color{#D61F06}{ \boxed{step~two}}$ .

$\dfrac{ 0 \times 0 \times 0 \times 0}{ 0\times 0 \times 0 } = 1$

It must be

$\dfrac{ 0 \times 0 \times 0 \times 0}{ 0\times 0 \times 0 } = Undefined$

Note

But why $\frac{0}{0}$ Is Undefined ?

Check out this Why $\frac{0}{0}$ Is undefined

The first was made in the $\boxed{\text{step 2}}$ .

$\dfrac{ 0 \times 0 \times 0 \times 0}{ 0\times 0 \times 0 } \text{Is undefined}$

Note: See this article.

Division by 0 is not defined!