Another 200 Followers problem!

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$4^{2005}-4^{2004}$

Take $4^{2004}$ common, you get

$\implies$ $4^{2004}\times \left(4-1\right)$

$\implies$ $4^{2004} \times 3 = \boxed{2^{4008}\times 3}$

4^2004x(4-1)=4^2004x3=2^4008x3

4^2005-4^2004 =4^2004(4-1) =4^2004×3 =(2^2)^2004×3 =2^(2×2004)×3 =2^4008×3

separate the same number of numbers: $4^{2005} - 4^{2004}$ because these numbers have the following elements: $4^{2004}$ then take the number $4^{2004}$ to be like this: $4^{2004} \times (4 - 1)$ = $4^{2004} \times 3$ because there is no answer, the number is reduced to: $2^{4008} \times 3$

⬜ =4^2004 4 ⬜ - ⬜ = 3 ⬜

the ans is 2 because if 4

(4^2005/ 4^2004 - 4^2004/4^2004 ).4^2004 = 3 . 4^2004 = 3. 2^4008

4^2004 = x ..................... 4^2005 = 4^2004 * 4 = 4x ..................... 4x - x = 3x ..................... 3 * 4^2004 = 3 * (2^2)^2004 .................... 3*2^4008

A little bit overrated , isn't it ???