Another Combination!

Sum of the three digit will be odd only if

• all the three digits are odd.
• only one digit odd, rest two are even.

Now,

Digits with all odd number $with repetition$ will be: $\boxed{5}×\boxed{5}×\boxed{5}= \boxed{125}$

Numbers with one odd and two even:

• 1) $\boxed{even} \boxed{even}\boxed{odd}$

Total cases $4×5×5=\boxed{100}$

• 2) $\boxed{even} \boxed{odd}\boxed{even}$

Total cases $4×5×5=\boxed{100}$

• 3) $\boxed{odd} \boxed{even}\boxed{even}$

Total cases $5×5×5=\boxed{125}$

Which brings the total to $125+100+100+125=\boxed{450}$