Let n 1 < n 2 < n 3 < n 4 < n 5 be positive integers such that their sum is 20. Find the number of distinct ordered solutions for ( n 1 , n 2 , n 3 , n 4 , n 5 ) .
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There are only 7 solutions satisfying n 1 < n 2 < n 3 < n 4 < n 5
( 1 , 2 , 3 , 4 , 1 0 ) , ( 1 , 2 , 3 , 5 , 9 ) , ( 1 , 2 , 3 , 6 , 8 ) , ( 1 , 2 , 4 , 5 , 8 ) , ( 1 , 2 , 4 , 6 , 7 ) , ( 1 , 3 , 4 , 5 , 7 ) , ( 2 , 3 , 4 , 5 , 6 )
can you list the actual ordered pairs, please? I only found 2.
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Possible solutions are (1, 2, 3, 4, 10) (1, 2, 3, 5, 9) (1, 2, 3, 6, 8) (1, 2, 4, 5, 8) (1, 2, 4, 6, 7) (1, 3, 4, 5, 7) (2, 3, 4, 5, 6) Hence 7 solutions are there.
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thank you very much. I do these problems at like 3am to 6am and my brain must have shut down thaty night lol
Can you please elaborate how come u directly jumped to the conclusion that the number of solutions is 7?
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