Another Direct and Inverse Variation Functions Question

Geometry Level 1

Given that y = 1 x 1 y = \frac 1{x-1} , find the domain of x x .

x < 1 x<1 x = 1 x=1 x > 1 x>1 x 1 x \ne 1

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

3 solutions

Isabella Yan
Feb 27, 2015

if x=1... 1-1=0 There's no such thing called 'any number/0'!

Max Higgins
Jun 12, 2021

This is really easy. You can't divide by zero, so you have to ask yourself: What can I put for the variable X that makes the denominator equal to zero? So, you set the bottom not equal to zero and then you add 1 to both sides. It then tells you that X can't be equal to 1. Hope this helped!

Parth Panchal
Apr 23, 2015

In the equation For x=1 , denominator becomes 0 thus it becomes undefined in Real Number System (R) & For any other value of x except 1 we get value of y . Thus the solution set is R - {1}

Thus the solution set is R - {1} why?

Mr. Ryan - 2 years, 4 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...