Another google problem

each couple will have 1 son. mean boys per couple =1.
probability of of having 0 girls = 1/2(0.5 chance that first is boy).
probability of having 1 girl = 1/4 (0.5 first is girl *0.5 second is boy).
and so on.
mean girls per couple= $sum_{i=1}^{infinity}$ i/ $2^{i+1}$ =1.
thus boys/girls =1

it was a mere guess man!

Ignoring the circumstances, each time a couple is going to have a child, the probability that the child is a boy is $\frac{1}{2}$ So having a child $n$ times, the expected number of boys is $\frac{n}{2}$ and the expected ratio is $1:1$

Notice that the probability of having a boy is independent of whether the previous child is a boy or not.

What this problem is asking is, "If you want to flip a coin until you get heads and you repeat the experiment for a long time, what's the head to tails ratio?" Just because you're ending the experiment when you see heads doesn't mean the probability of heads has changed.

Python 3.4:

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from random import choice
from time import time
p = 0
q = 0
def intercourse():
    # this is actually how babies are made
    boys = 0
    girls = 0
    boy = False
    while not boy:
        boy = choice((True, False))
        if boy:
            boys += 1
        else:
            girls += 1
    return boys, girls
end = time() + 10
# make babies for 10 seconds
while time() < end:
    new_boys, new_girls = intercourse()
    p += new_boys
    q += new_girls
print("p/q is about", round(p/q, 2))

You should ask for "expected" value of p/q...

Using probability,where probability of getting girl and boy is equal

$\frac{P(GettingBoys)}{P(GettingGirls)} = \frac{P(B) + P(GB) + P(GGB) + ...}{P(G) + P(GG) + P(GGG) + ...} = \frac{0.5 + 0.5^2 + 0.5^3 + ...}{0.5 + 0.5^2 + 0.5^3 + ...} = 1$

the\quad probabilities\quad for\quad both\quad boy\quad and\quad girl\quad are\quad the\quad same....hence\quad the\quad answer\quad 1