Another calculus problem
Level
pending
If y = (1 - sin 2x/1 + sin 2x)^1/2
Then find dy/dx
cosec^2 (x-pi/4)
sec^2 x
sec^2 (x-pi/4)
cosec^2 x
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1 solution
y=1-sin2x/1+sin2x
hence y=cosx-sinx/cox+sinx
dividing by cosx
y=1-tanx/1+tanx
y=tan(pi/4 - x)
dy/dx=sec^2 (pi/4-x)