Four fair dice D1 , D2 , D3 , and D4 each having six faces numbered 1, 2, 3, 4, 5 and 6 are rolled simultaneously. The probability that D4 shows a number appearing on one of D1 , D2 and D3 is :
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The probability that D4 shows a number not appearing on any of D1, D2 and D3 is ( 6 5 ) 3 = 2 1 6 1 2 5 ,so the probability that D4 shows a number appearing on one of D1, D2 and D3 is 1 − 2 1 6 1 2 5 = 2 1 6 9 1