Another problem where the arbitrarily chosen number is 2018

What is the smallest positive integer n n such that 2018 ! n \frac{2018!}{n} isn't an integer?


The answer is 2027.

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2 solutions

X X
May 12, 2018

Find the first prime larger than 2018 ,and get 2027

Exactly...(+1)

Ravneet Singh - 3 years ago
Giorgos K.
May 11, 2018

Using M a t h e m a t i c a Mathematica

n=1;While[IntegerQ[2018!/n++]];n-1

returns 2027 \boxed{2027}

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