Find the sum of all four-digit numbers that give a remainder of 47 when divided by 197, and a remainder of 37 when divided by 198.
This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try
refreshing the page, (b) enabling javascript if it is disabled on your browser and,
finally, (c)
loading the
non-javascript version of this page
. We're sorry about the hassle.
Assume that the four-digit number is N
According to the question 1 9 7 m + 4 7 = 1 9 8 l + 3 7 = N = > 1 9 7 m + 1 0 = 1 9 8 l = > 1 9 7 ( m − l ) = l − 1 0
As 1 9 7 is a prime number so 1 9 7 ∣ l − 1 0
So, l = 1 0 , 2 0 7 , 4 0 4 , . . . . . . .
The four digit number will be for l = 1 0 and the number is N = 2 0 1 7