Another spring problem

In the diagram, there is a rigid link AB of length 50 cm 50\text{ cm} . It is attached to a frictionless bearing at point A. It can rotate about the bearing in the plane of the picture. The bearing is mounted on a rigid surface. A spring of spring constant k = 200 Nt / M k = 200 \text{ Nt / M} is attached to link AB at a point 25 cm 25\text{ cm} from bearing A. The spring is perpendicular to link AB, and its other end is anchored to a rigid surface. What is the effective spring constant at point B? (In Nt/M \text{Nt/M} )?

200 50 25 100 400

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1 solution

Aniket Sanghi
Aug 16, 2016

I did it like this - ( Using SHM concepts )

Turn the rod clockwise by angle θ < < < π \theta <<< \pi .

Then the Torque applied by the spring is

τ = r × F = l × k x = l × k ( l θ ) \tau = r × F = l × kx = l × k ( l \theta ) ,

where l is the distance of spring from A . And since x < < < 1 x <<< 1 it can be treated as an arc of circle and hence x = l × θ x = l × \theta

Now equate the case when spring with spring constant 200 N/m at 25 cm and when spring with spring constant K at 50 cm .

( 0.25 ) 2 × 200 × θ = ( 0.5 ) 2 × K × θ ( 0.25)^2 × 200 × \theta = (0.5)^2 × K × \theta

On solving we get K = 50 N / m \boxed{K = 50N/m }

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