Another Trigonometric Model Among Temperatures

Geometry Level 4

In 2015, students have followed some daily average temperature registrations in Vicenza, Veneto, Italy. The analysis of another data gathered in previous years convinced the scholars that the daily average temperature follows a trend schematically described by the following function family:

f ( t ) = sin 2 ( t 6 4 ) sin ( t 6 4 ) cos ( t 6 4 ) + a cos 2 ( t 6 4 ) + b \large f(t)=\displaystyle{\sin^2\left ( \dfrac{t-6}{4} \right )-\sin \left ( \dfrac{t-6}{4} \right ) \cos \left ( \dfrac{t-6}{4} \right )+a \cdot \cos^2 \left ( \dfrac{t-6}{4} \right )+b}

where t t is time expressed in months of 30 days. For example, on 13 March 2015, 72th day of the year, time t t is 72 30 = 2.4 \dfrac{72}{30}=2.4 .

Find the value of parameters a a and b b knowing that on 13 March 2015 the average temperature was 11.0 1 C 11.01^\circ C and on 26 June of the same year was 3 2 C 32^\circ C .

Using the parameters found previously, determine the days when the average temperature was higher than 2 0 C 20^\circ C and lower than 3 0 C 30^\circ C .

(The temperature is measured in Celsius.)

Between April 11 and May 28; between July 24 and September 8 Between March 26 and June 13; between August 17 and October 31 Between April 5 and June 8; between August 13 and September 16 None of the other answers Between March 16 and May 30; between July 12 and September 26

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