What is
Hint: The expression can be expressed as
Note: Please try to do this problem without resorting to factoring out the eighth degree equation, or using the calculator, or using CALCULUS
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Clearing all the square roots leads to a messy degree 8 polynomial, which is only solvable numerically (realistically - it does factorise into a quadratic and two cubics, but this is not obvious). It also has eight real roots, seven of which are not the solution we're looking for.
Since a numerical approach is needed anyway, a much easier method is to simply pick a sensible start point x 0 , and iterate the given function as x n + 1 = 4 + 4 + 4 − x n for n ≥ 1 . It's not guaranteed this will converge, but in this case we're lucky.
What might a sensible start value be? Well, by inspection, x must be in the interval ( 0 , 4 ) , so x 0 = 2 isn't a bad guess.
Plugging in to the above scheme, we find x 1 = 2 . 5 1 5 3 2 … , x 2 = 2 . 5 0 6 8 7 … , x 3 = 2 . 5 0 7 0 2 … , quickly converging on the solution.