What is the answer for 1+ 2 + 3 + 4 + 5 + 6 +7 + 8 ...... + 99 ?
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Indeed, the formula above came from this formula: 2 n ( a + l ) where n is the number of the terms in certain ARITHMETIC PROGRESSION (a sequence which satisfy m 2 − m 1 = m 3 − m 2 . = . . . = m n + 1 − m n where m i are the terms in the sequence) and a is the first term and l is the last term.
same as I did, liked!
did the same thing.
I also did this
Count by using this method: [ 1 + 99 = 100 , 2 + 98 = 100 , 3 + 97 = 100 ] continuously until 49 + 51 = 100. Therefore you had already got 49 hundreds which is 4900, Then, add 50 into it and you will get 4950.
Yay! Gaussian pairing tool.
I did like this!! all that it requires is called common sense!! ha ha!
smart!
Intelligent!
We know that the sum of 1st n natural number is given by
sum of 1st n natural n.o =n(n+1)/2
Here n=99
=>99(99+1)/2=4950
took 40 secs https://brilliant.org/discussions/thread/sum-of-all-numbers-in-between/?ref_id=435792
45 tens X 10 + 45 ones X 10 = 4950
n(n+1)/2 = 99*50 = 4950
Gauss Solution: Add up the last ends of the numbers until the median number is left out. Add it also to the result of adding the end numbers.
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By using the sum of the first n consecutive numbers, we have 2 n ( n + 1 ) = 2 9 9 ( 1 0 0 ) = 4 9 5 0