Answer Within A Minute II

What is the answer for 1+ 2 + 3 + 4 + 5 + 6 +7 + 8 ...... + 99 ?


The answer is 4950.

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9 solutions

敬全 钟
Mar 27, 2014

By using the sum of the first n consecutive numbers, we have n ( n + 1 ) 2 = 99 ( 100 ) 2 = 4950 \frac{n(n+1)}{2}=\frac{99(100)}{2}=4950

Indeed, the formula above came from this formula: n 2 ( a + l ) \frac{n}{2}(a+l) where n is the number of the terms in certain ARITHMETIC PROGRESSION (a sequence which satisfy m 2 m 1 = m 3 m 2 . = . . . = m n + 1 m n m_2-m_1=m_3-m_2.=...=m_{n+1}-m_n where m i m_i are the terms in the sequence) and a is the first term and l is the last term.

敬全 钟 - 7 years, 2 months ago

same as I did, liked!

Evan Lee - 7 years, 2 months ago

did the same thing.

Jaydeep Parsana - 6 years, 10 months ago

I also did this

Ahmed Obaiedallah - 6 years ago
Wenn Chuaan Lim
Mar 27, 2014

Count by using this method: [ 1 + 99 = 100 , 2 + 98 = 100 , 3 + 97 = 100 ] continuously until 49 + 51 = 100. Therefore you had already got 49 hundreds which is 4900, Then, add 50 into it and you will get 4950.

Yay! Gaussian pairing tool.

敬全 钟 - 7 years, 2 months ago

I did like this!! all that it requires is called common sense!! ha ha!

Pradeep Nagashetti - 7 years, 1 month ago

smart!

Nilangini Gupta - 7 years, 1 month ago

Intelligent!

Karan Kunder - 6 years, 11 months ago
Vishal S
Dec 21, 2014

We know that the sum of 1st n natural number is given by

sum of 1st n natural n.o =n(n+1)/2

Here n=99

=>99(99+1)/2=4950

Dev Od
Dec 2, 2014

n(n+1)/2 which 99(100)/2=4950

Pavan Rohit
Oct 22, 2014

1+99/2 multiplied by 99

Aareyan Manzoor
Oct 8, 2014

took 40 secs https://brilliant.org/discussions/thread/sum-of-all-numbers-in-between/?ref_id=435792

Rocky El-Azar
Apr 25, 2014

45 tens X 10 + 45 ones X 10 = 4950

n(n+1)/2 = 99*50 = 4950

Lance Fernando
Aug 1, 2015

Gauss Solution: Add up the last ends of the numbers until the median number is left out. Add it also to the result of adding the end numbers.

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