Ant on butter

Geometry Level 1

One day, Anty the ant found a block of butter. He measured it to be 2cm by 2cm by 5 cm. He climbs over the butter, when oops! The butter hangs off the edge of a table, and he can't support his weight upside down, and he falls onto the ground, a bit annoyed, since that hurt. He started climbing at the square face 90 degrees from gravity, and then only turned 90 degrees to go to the next face with a constant velocity of 10 cm/s(He once competed in the ant olympics). How long did he climb the stick of butter before falling off?

Note: The ant was fine afterwards and joined all his ant friends.

2 s 0.2 s 0.4 s 0.9 a 0.5 s 4 s 0.7 s 9 s

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1 solution

Alex Wang
Aug 25, 2018

When the ant gets past the "fall off line", he becomes upside down, so he falls. He would have to travel 2+5+2 cm(sorry, my units were messed up, wherever I put m, think "cm")to fall off, which is 9 cm. He travels at 10 cm per second(whereever I put 0.1 m/s, its supposed to be 10 cm/s, sorry) so he gets to the "fall off line" at 0.9 s.(He is fast!)

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