Antibonacci Sequence #2

Regarding the previous problem in this set , we know the first 4 backwards Fibonacci numbers. Using the method that you learned, keep going backwards. Besides being is reversed order, how does the forwards sequence ( F n F_n ) contrast to the backwards sequence ( F n F_{-n} )?

Note for clarity : 2 n + 1 -2n+1 means a negative number that is odd, and 2 n -2n means a negative number that is even.

All of the odd numbers in the backwards sequence are negative. F 2 n + 1 F_{-2n+1} is always positive and F 2 n F_{-2n} is always negative. All of the even numbers in the backwards sequence are negative. They are the same sequences. F 2 n + 1 F_{-2n+1} is always negative and F 2 n F_{-2n} is always positive.

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1 solution

Blan Morrison
Jan 24, 2018

Using the method previously used, we can find the numbers in the sequence between F 7 F_{-7} and F 7 F_7 : 13 , 8 , 5 , 3 , 2 , 1 , 1 , 0 , 1 , 1 , 2 , 3 , 5 , 8 , 13 13,~-8,~5,~-3,~2,~-1,~1,~0,~1,~1,~2,~3,~5,~8,~13

If we observe, we can see that every other number in the backwards sequence is negative. Upon closer observation, we can see that every ( 2 n + 1 ) th (-2n+1)^\text{th} number is negative. This pattern will clearly continue, so F 2 n + 1 F_{-2n+1} is always positive and F 2 n F_{-2n} is always negative.

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