Any number of times?

The single digit positive integer X X satisfies this peculiar property:

If X X is multiplied by itself any number of times, then the last digit of this resultant number is still X X .

Which of the following can be possible value of X X ?

9 7 6 8

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

2 solutions

Toshit Jain
Mar 1, 2017

The numbers with cyclicity 1 are the possible values of X. Among the given options , only 6 has cyclicity 1 . Therefore , 6 can be the possible value of X.

Rafi Pepe
Feb 28, 2017

We try to multiply all number with itself and then we know that the one of those choices which satisfy the property is 6

No, you have not shown that 6 is the answer.

How do you know that there isn't a positive integer n n such that the last digit of 6 n 6^n is not 6?

Pi Han Goh - 4 years, 3 months ago

Your problem is not logical at all, must rethink their.

Ali Altameme - 4 years, 3 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...