If and follows a harmonic progression (in that order), which of these answer choices equals to ?
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A more elementary solution: a = n 1 ; b = n + m 1 ; c = n + 2 m 1 ; d = n + 3 m 1 . The given sum is n ( n + m ) 1 + ( n + m ) ( n + 2 m ) 1 + ( n + 2 m ) ( n + 3 m ) 1 = n ( n + m ) ( n + 2 m ) ( n + 3 m ) ( n + 2 m ) ( n + 3 m ) + n ( n + 3 m ) + n ( n + m ) = n ( n + m ) ( n + 2 m ) ( n + 3 m ) 3 n 2 + 9 n m + 6 m 2 = n ( n + m ) ( n + 2 m ) ( n + 3 m ) 3 ( n + m ) ( n + 2 m ) = n ( n + 3 m ) 3 = 3 a d .