Arash's Sequence 5

485;323;215;143;95

So, here is my solution :

485+1=486 486/3=162 485-162=323

323+1=324 324/3=108 323-108=215

...

95+1=96 96/3=32 95-32=63

So 63 is the solution

getting the difference(1) for each 2 consecutive terms

485 - 323 = 162

323 - 215 = 108

215 - 143 = 72

143 - 95 = 48

we can also observe that the ratio of each 2 consecutive terms of difference (1)

108/162 = 2/3

72/108 = 2/3

48/72 = 2/3

So the next subtrahend for the sequence is

X/48 = 2/3

X = 32

then the next is 95 - 32 = 63