Arc-ed up

Geometry Level 1

arcsin 1 + arccos 1 + arctan 1 + arccot 1 + arcsec 1 + arccsc 1 = ? \large \arcsin 1 + \arccos 1 + \arctan 1 + \text{arccot} \, 1 + \text{arcsec} \, 1 + \text{arccsc} \,1 = \ ?

0 0 π 4 \dfrac{\pi}{4} π 2 \dfrac{\pi}{2} 3 π 4 \dfrac{3\pi}{4} π \pi 5 π 4 \dfrac{5\pi}{4} 3 π 2 \dfrac{3\pi}{2} 7 π 4 \dfrac{7\pi}{4}

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2 solutions

Steven Yuan
Jan 13, 2015

arcsin 1 = π 2 . arccos 1 = 0. arctan 1 = π 4 . arccot 1 = π 4 . arcsec 1 = 0. arccsc 1 = π 2 . \begin{aligned} \arcsin 1 &= \frac{\pi}{2}. \\ \arccos 1 &= 0. \\ \arctan 1 &= \frac{\pi}{4}. \\ \text{arccot} \, 1 &= \frac{\pi}{4}. \\ \text{arcsec} \, 1 &= 0. \\ \text{arccsc} \, 1 &= \frac{\pi}{2}. \end{aligned}

We can confirm these by taking the trigonometric functions of these values to see if they get 1. 1. Thus,

arcsin 1 + arccos 1 + arctan 1 + arccot 1 + arcsec 1 + arccsc 1 = π 2 + 0 + π 4 + π 4 + 0 + π 2 = 3 π 2 . \begin{aligned} \arcsin 1 + \arccos 1 + \arctan 1 + \text{arccot} \, 1 + \text{arcsec} \, 1 + \text{arccsc} \, 1 &= \frac{\pi}{2} + 0 + \frac{\pi}{4} + \frac{\pi}{4} + 0 + \frac{\pi}{2} \\ &= \boxed{\frac{3\pi}{2}}. \end{aligned}

there was no option as 3pi/2

Rishi Sharma - 6 years, 4 months ago
Paola Ramírez
Jan 17, 2015

arcsin 1 = π 2 \text{arcsin}1=\frac{\pi}{2}

arccos 1 = 0 \text{arccos}1=0

arctan 1 = π 4 \text{arctan}1=\frac{\pi}{4}

arccot 1 = π 4 \text{arccot}1=\frac{\pi}{4}

arcsec 1 = 0 \text{arcsec}1=0

arccsc 1 = π 2 \text{arccsc}1=\frac{\pi}{2}

arcsin 1 + arccos 1 + arctan 1 + arccot 1 + arcsec 1 + arccsc 1 = 3 π 2 \arcsin 1 + \arccos 1 + \arctan 1 + \text{arccot} \, 1 + \text{arcsec} \, 1 + \text{arccsc} \,1 =\boxed{\frac{3\pi}{2}}

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