Arctangent family

Calculus Level 5

In the diagram above, the black curves show some members of the family f c ( x ) = c + arctan x . f_c(x) = c + \arctan x. The red curve intersects all members of this family perpendicularly.

If the red curve is described by the function g g , and g ( 0 ) = 0 g(0) = 0 , how much is g ( 6 ) g(-6) ?


The answer is 78.

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1 solution

The condition of perpendicularity can be written as f c ( x ) g ( x ) = 1 , f_c'(x)\cdot g'(x) = -1, wherever f c ( x ) = g ( x ) f_c(x) = g(x) . The derivative of the arc tangent function is known: 1 1 + x 2 g ( x ) = 1 g ( x ) = x 2 1. \frac 1{1+x^2}\cdot g'(x) = -1\ \ \ \therefore\ \ \ g'(x) = -x^2-1. Integrating, we get g ( x ) = 1 3 x 3 x + k , g(x) = -\tfrac13x^3 - x + k, but since g ( 0 ) = 0 g(0) = 0 the integration constant should be k = 0 k = 0 .

Finally, g ( 6 ) = 1 3 ( 6 ) 3 ( 6 ) = 1 3 216 + 6 = 72 + 6 = 78 . g(-6) = -\tfrac13(-6)^3 - (-6) = \tfrac13\cdot 216 + 6 = 72 + 6 = \boxed{78}.

Basically just orthogonal trajectories of a given family. Clear solution though. (+1)

A Former Brilliant Member - 5 years, 1 month ago

I did the same after some disorientation. Clever task => my congratulation!

Andreas Wendler - 5 years, 1 month ago

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