Arcturus Motion

When sunlight is passed through a prism, it splits into a spectrum of different wavelengths λ \lambda (different colors). On careful examination, we notice some missing bands, which indicate the presence of different elements such as hydrogen, sodium, and magnesium that absorb light of specific wavelengths.

The spectrum of a distant star, Hayesmark, which is known to have the same elemental composition as the Sun, was measured, and the data is shown below.

What can we infer from the spectra?


Hint : The Doppler effect tells us how the wavelength measured by an observer depends on their relative velocity, v , v, with the source. It changes according to λ o λ s = c + v c v , \frac{\lambda_o}{\lambda_s} = \sqrt{\frac{c + v}{c - v}}, where c c is the speed of light.

This star is named in honor of Mark Hayes , who pointed out a problem with the star we originally chose.

Hayesmark is moving towards us Hayesmark is moving away from us The distance between Hayesmark and us remains constant

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4 solutions

The light from Hayesmark shows a redshift compared to the sun, meaning that the wavelength we receive is less than the emitted wavelength. This is symptomatic for the source and recipient moving away from each other.

The analogous effect on sound waves is more familiar; when a car moves away from us, we hear a lower pitch (longer wavelength) than usual.


Suppose a "crest" of the wave is emitted. During the next period τ \tau , the wave travels λ s = c τ \lambda_s = c\tau toward us. Meanwhile, Hayesmark moves away from us over a distance v τ v\tau before the next "crest" is emitted. Thus the spacing between the "crests" is really λ o = λ s + v τ = λ s ( 1 + v c ) = λ s c + v c . \lambda_o = \lambda_s + v\tau = \lambda_s\left(1 + \frac v c\right) = \lambda_s\frac{c + v}c. While this gives qualitatively correct results (and quantitative for small values of v v ), it must be adjusted for effects of relativity. This leads to the equation quoted in the problem statement. Note that if β = v / c 1 \beta = v/c \ll 1 , c + v c v = 1 + β 1 β ( 1 + β ) ( 1 + β ) 1 + 2 β 1 + β = c + v c , \sqrt{\frac{c+v}{c-v}} = \sqrt{\frac{1 + \beta}{1 - \beta}} \approx \sqrt{(1+\beta)(1+\beta)} \approx \sqrt{1 + 2\beta} \approx 1 + \beta = \frac{c + v}c, which is our non-relativistic result.

Moderator note:

Redshift turned out to be an important clue in dating the age of the universe. We can use redshift to detect the changing distances of varying stellar objects as the universe expands, and then "run the tape backwards" in time until we reach the Big Bang, giving us an estimate of 13.8 billion years.

Isn't your analogy of sound waves contradicting the answer? When a source moves away from us, the wavelength we receive is longer than the emitted wavelength, which follows that the wavelength shift shown depicts that the star is moving towards us, as observed wavelength is shorter, not longer. Please tell me if I am missing something here. Unable to understand as per the analogy in your solution. In the math as well, you have taken that the spacing between crests increases, when in fact it has decreased (shifted towards blue).

Aseem Raj Baranwal - 3 years, 6 months ago

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Note that Hayesmark is the spectrum on top, the Sun at the bottom. The absorption lines in the spectrum of Hayesmark are to the right of the corresponding lines for the sun, i.e. toward longer wavelengths.

Arjen Vreugdenhil - 3 years, 6 months ago

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Apologies, and thanks very much. Don't know how I took them to be the converse.

Aseem Raj Baranwal - 3 years, 6 months ago

Why is spectrum going from right to left? Is it taken from some Arabic site?

Alex Ander - 3 years, 6 months ago

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No, it is arranged by wavelength rather than by frequency. This is not uncommon.

Arjen Vreugdenhil - 3 years, 6 months ago

The formula is a nice touch to distract us but very little was defined. Is the positive direction of the velocity toward or away from Hayesmark? Which stars do the subscripts o and s refer to?

Stephen Meskin - 3 years, 6 months ago

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v v is the velocity component of separation between the source and observer in the direction of the line joining them.

S stands for source and O for observer.

Arjen Vreugdenhil - 3 years, 6 months ago

I need a lesson on how to read the spectrum. It appears to me that Hayesmark has more blue than the sun.

Joe Jones - 3 years, 6 months ago

I really want to understand this... But is this spectrum is not showing us how the planet moves. We need two spectrums to conclude that the planet is moving. But the two spectrums are about two different planets so we only can conclude that the planet Hayesmark is further than the sun right?

Sorry for mine broken english i tried tot do mine best

But would someone explane this to me i loved to understand IT in forward thanks

Mike Gerrits - 3 years, 6 months ago

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First of all, this is about a star , not a planet. The reason why we can compare the two stars is that they emit similar patterns of light.

The Doppler shift gives no information about distance , but only about the relative speed between the source (at moment of emission) and receiver (at moment of reception). Since we move around the sun in nearly circular motion, we know the sun is neither approaching nor receding. Therefore the light of the sun can be used as a standard for "no motion". Any shift of the spectrum indicates that a star is either approaching (blue shift) or receding (red shift).

Arjen Vreugdenhil - 3 years, 6 months ago

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Ahhh thats really clever tanks :)

Mike Gerrits - 3 years, 6 months ago
Yash Ghaghada
Dec 5, 2017

Simply because universe is expanding, the distance between stars should also increase

The fact that the universe is expanding does not mean that the distance between every star is increasing. The Andromeda galaxy is moving towards us and it appears blueshifted.

Pranshu Gaba - 3 years, 6 months ago

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Due to the universe constantly expanding.. my answer was also correct

Nicholas B - 3 years, 6 months ago

What would our universe look like if, from birth, each star did not or simply could not get closer to another star? I'm guessing after 14 billion years, most stars would be equidistant from its neighbors, as the younger stars push the older stars away from ground zero......an impossible Borg-ish grid system of stars that could not have formed in the first place....because matter moving closer together is how stars are born. Thank you, Mr. Sagan. We are all children of the "blueshift" resulting from the kaleidoscopic chaos caused by the first redshift. Each child of this earth and each atom of this universe owes its existence to matter exploding away from and towards matter.

IF the universe is expanding AND will always continue expanding.... "The Big Freeze"... Even then stars or their remnants would still collide albeit with less and less frequency as time went on..........

Oh yeah....and the math....the math was good too. ;)

Raul San Miguel - 3 years, 6 months ago
Kunal Solanke
Dec 9, 2017

Acc to me the the spectrum of the other satr mentioned has more larger wavelength spectra as compared to that of sun as both should be measured from same place so ........the wavelngth is in general form lambda =v+ct .......and hence considering it as source its moving away

Tristan Chaang
Dec 6, 2017

The spectrum is shifted slightly to the right than our sun’s, so light is travelling at a slightly longer wavelength / lower frequency relative to our sun. By the Doppler effect this means that the source (which is the star) should be moving away relative to us.

"...which is known to have the same elemental composition as the Sun..." How do we know this?

Edward Rogers - 3 years, 6 months ago

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Because once you've accounted for red (or blue) shift, those black lines on both spectra would line up, indicating the presence of the same elements?

Just guessing, I'm a bit out of my league with the Doppler effect once you get past "nee na nee na nee naw na naw na naw" 😆

Alex Smith - 3 years, 6 months ago

Alex is right. After adjusting for redshift, the spectra of the two stars look very similar. The spectra that is measured has more detail than black bands, the intensity at every wavelength can be measured and plotted like the one shown below. Each element has a signature absorption spectrum. The spectrum of the star is a superimposed combination of spectra of different elements. This lets us know what elements make up the star.

Pranshu Gaba - 3 years, 6 months ago

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