If all the resistors in the circuit are of 2 Ω , find the value of the equivalent resistance(in Ohms).
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@Saya Suka How did you do that? My method was by potentials and the only unknown node at average voltage by symmetry.
Let the nodes be named as:
This is equivalent to:
So,
R A B 1 = 4 1 + 2 1 + 4 1
R A B = 1 Ω
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1/R = 1/(2 + 2) + 1/2 + 1/(2 + 2)
= 1/4 + 1/2 + 1/4
= 1/1
R = 1 Ω