If the sum of all roots to the equation above equals to for some positive integer and , find the value of .
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Equation: x 2 + x − ∣ x ∣ − 4 = 0
CASE I: If x ≥ 0 , then equation becomes x 2 + x − x − 4 = 0
⇒ x = ± 2
So, x = 2 is a solution in this case.
CASE II: If x < 0 , then equation becomes x 2 + x − ( − x ) − 4 = 0
⇒ x 2 + 2 x − 4 = 0
⇒ x = − 1 ± 5
So, x = − 1 − 5 is a solution in this case.
Therefore, S u m = 2 − 1 − 5
⇒ 1 − 5
⇒ a + b = 1 + 5 = 6 ⌣ ¨