A train, travelling at a uniform speed for 360 km, would have taken 48 minutes less to travel the same distance if its speed were 5 km/h more. Find the original speed of the train.
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Let x be the original speed.
360(1/x - 1/(x+5)) = 4/5.
0 = x^2 + 5x - 2250.
= (x - 45)(x + 50).
x = 45 >= 0