How many of the following 10 numbers are prime?
1 , 2 0 1 , 2 2 0 2 , 3 2 0 3 , 4 2 0 4 , 5 , 2 0 5 .
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nicely solved !!!
the answer is 2,3, and 5 because 1 isn't prime 4= 2^2, 201= 3 * 67, 202 = 2 * 101, 203= 7 * 29 , 204 = 2^2 * 3 * 17 ,and 205 = 5 * 41
Prime Numbers only have two divisors:
1 and the number itself
2 3 5 are the prime number.
Thus only 3 numbers are prime number.
1 is not a prime number, 201 divided by 3 is 67, 202 divided by 2 is 101, 203 divided by 7 is 29, 204 divided by 2 is 102, and 205 is divided by 41. So the only numbers left are 2, 3, and 5. So the answer is 3.
nyc
Prime numbers are numbers that can be equally divided by 1 and itself. Just think about the numbers carefully and u will get the answer. U can also check the prime numbers list if u like.
Only 3 i.e. 2,3 and 5 are prime.
Using this list to View Numbers What are cousins, we have the following Prime Numbers : 2 , 3 , 5
201 is divisible by 3.
202,4 and 204 are divisible by 2.
1 is neither prime nor composite and 205 is divisible by 5.
So, only 2,3,5 are prime nos.
use the following python code and input the given values in 'n':
n=
c=0
for i in range(2,n+1):
x=n/i
if x in range(1,n+1):
c=c+1
if c<=1:
continue
else:
print('number is not prime')
break
we know 2,3,5 are primes only in given nos
Prime numbers are numbers whose only factors are one and itself. 1 isn't prime because it only has itself as a factor, 2 is prime, 3 is prime, 4 is composite, 5 is prime, 201 is composite, 202 is composite, 203 is composite, 204 is composite, and 205 is composite. That leaves us with 3 prime numbers. The correct answer is 3.
2 is the only even prime number 0 and 1 is not considered a prime number , 3 and 5..
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First neglect all even numbers except 2, as they are divisible by 2 - so we have {1, 2, 3, 5, 201, 203, 205}. Now remove numbers who have 5 or 0 at its units place except the number 5, as they are divisible by 5 - so we have {1, 2, 3, 5, 201, 203}. Now 1 is neither a prime nor a composite number - so {2, 3, 5, 201, 203}. Now, 201 is divisible by 3, as the sum of its digits is divisible by 3. So we have the set {2, 3, 5, 203}. Finally we get that 203 is divisible by 7, after some checking. So the final set which are prime are {2, 3, 5}. The answer is 3.