Two sportsman and went out for hunting and brought home 10 birds. The sum of squares of the number of shots fired by each was 2880, and the product of the number of shots fired by each was 48 times the product of number of birds killed by each. If had fired as often as and as often as then would have killed 5 more birds than If the number of birds killed by and are and respectively, then what is the value of
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Let the number of shots fired by A and B be x and y.
Let the number of birds killed by A and B be respectively a and b.
Given x × x + y × y = 2 8 8 0 . ----- (1)
Also given x × y = 4 8 × a b
The values of x and y which satisfy the condition (1) is 48 and 24.
Equating 4 8 × 2 4 to 4 8 × a b , product of a and b = 2 4 . We also know a + b = 1 0
So, the values of a , b can be 6 , 4 or 4 , 6 .
The last condition given eliminates 4,6 as below.
If the no of shots fired by A and B are switched then B kills 5 more than that of A, that is 3 , 8 .
So A fired more shots and killed more birds, so the values of a , b are 6 , 4 .
So ( a − b ) × ( a b ) − b = ( 6 − 4 ) × ( 6 × 4 ) − 4 = 4 4 .