An airplane has 4 engines. The probability for the engines to function are 2 1 , 3 2 , 7 3 and 8 7 respectively. The airplane can fly if at least 1 of the engines can function. The probability that the airplane can fly safely can be expressed as b a where a and b are positive coprime integers. What is the value of a + b ?
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Instead of finding directly to the probability of the airplane to fly safe, we can do it in the other way.
Main idea: Find the probability of the airplane to crash and get 1 subtract to it.
The probability for the engines to malfunction are 2 1 , 3 1 , 7 4 and 8 1 respectively. So, the probability for all engines to malfunction is 2 1 × 3 1 × 7 4 × 8 1 = 6 4 1
Now, if the airplane does not crash, what does it mean? Yes, it flies!
1 is the overall conditions, so we get 1 − 6 4 1 = 6 4 6 3 and we get 63+64=127
This is a helpful reminder: If you see a combinatorics problem that contain the words "at least", first count the instances you don't want to include.
Major typo: 84 not 64...other than that, great and humerus solution, I feel like more solutions should be written this way haha..
The probability for all engines to fail= 1/2 1/3 4/7*1/8=4/336=1/84 Therefore, the probability at least one engine works ( good enough to fly) is 1-1/84= 83/84. a+b=167
The plane will fly safely if at least one engine works . Therefore, we have to find the probability of at least one engine working.
The probability that at least one engine works is 1 − P ( all engines fail )
Now, probability that all engines fail is
( 1 − 2 1 ) × ( 1 − 3 2 ) × ( 1 − 7 3 ) × ( 1 − 8 7 )
Therefore we get the probability of all engines failing as
2 1 × 3 1 × 7 4 × 8 1 = 8 4 1
Remember that the probability of at least one engine working was
P ( at least one engine working ) = 1 − P ( all engines fail )
Thus, P ( at least one engine working ) = 1 − ( 8 4 1 ) = 8 4 8 3 giving us the answer 8 3 + 8 4 = 1 6 7
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The plane will not fly only if all of the engines malfunction. The chances that the engines malfunction are 2 1 , 3 1 , 7 4 , 8 1 respectively. The chance that all the engines malfunction is 2 1 × 3 1 × 7 4 × 8 1 = 8 4 1 Therefore, the chance that at least one of the engines function is 1 − 8 4 1 = 8 4 8 3 And 8 3 + 8 4 = 1 6 7