Find least positive integer n such that
(n+20)+(n+21)+........(n+100) is a perfect square..
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Here ,This is an Arithmetic Progression with first term =n+20 Last term=n+100 Number of terms=8
Therefore its sum is,
81/2×(n+20+n+100) =81(n+60)
So,for 81(n+60) to be a perfect square n+60=K^2
So least possible value of n=4..