Area.

Calculus Level 5

The point ( [ P + 1 ] , [ P ] ) ([P+1],[P]) , (where [.] denotes the greatest integer function) lies inside the region bounded by the circle x 2 + y 2 − 2 x − 15 = 0 x^{2}+y^{2}-2x-15=0 and x 2 + y 2 − 2 x − 7 = 0 x^{2}+y^{2}-2x-7=0 ,then P lies in

(-1,2) None of these. [-1,0)U[0,1)U[1,2) [-1,2)-{0,1}

Keshav Tiwari by Keshav Tiwari , 23, India

This section requires Javascript.
You are seeing this because something didn't load right. We suggest you, (a) try refreshing the page, (b) enabling javascript if it is disabled on your browser and, finally, (c) loading the non-javascript version of this page . We're sorry about the hassle.

1 solution

For the point to lies strictly in the area b/w the circles [P+1] can have value {-2,4} and [P] can have value {-3,3}.
So P can have values (-3,-2)U(3,4). Please correct me if I am wrong

0 Helpful 0 Interesting 0 Brilliant 0 Confused

I got the result that no such P exists.

Ankit Kumar Jain - 2 years, 10 months ago

0 pending reports

×

Problem Loading...

Note Loading...

Set Loading...