A rectangle with an area of 60 square centimeters and whose length is twice its width is inscribed in a semicircle. Find the area of the square that could be inscribed in a circle with the same radius.
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If we "mirror" the rectanle and the semicircle , we obtain the circle and the sqare we are looking for ( since lenght =2*width) so the area is twice the rectangle area so is 120.