In the above diagram.
Given the unit circle with a center at A and the segment ED tangent at the point C.
What is the area of the quadrilateral CDOG.
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The segment EC is equal to the tangent of the angle EAC. Likewise the segment CD is equal to the cotangent of that angle. The area of the rectangle ELHD is thus: ( tan + cot ) 2 = tan 2 + 2 × tan cot + cot 2 = tan 2 + cot 2 + 2 cos sin sin cos = tan 2 + cot 2 + 2
The rectangles CDOG and NLMG are each equal to the product of the tangent and cotangent of the angle EAC. Hence each of them has the value one.
Can you Show this construction leads to a unique solution? Or at least solutions with equal area?
Edit: I missread an thought youre looking for the area of the big square.
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