Area of Lunar Moons (1)

Geometry Level 2

Semicircular arcs are constructed on the sides of a triangle as shown above.

Estimate the sum of the green area and the blue area to the nearest whole number.

24 36 20 14 30

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1 solution

Aaryan Maheshwari
Feb 12, 2018

Refer to the given diagram:

Area of the biggest semicircle = π R 2 2 = 25 π 2 =\dfrac{\pi\text{R}^2}{2}=\dfrac{25\pi}{2}

Area of Δ ABC = 1 2 × 6 × 8 = 24 \Delta\space \text{ABC}=\dfrac{1}{2}\times\space 6\times\space 8=24 (As it is right angled)

Area of Red region + + Area of yellow region = = 25 π 2 24 = 25 π 48 2 \dfrac{25\pi}{2}-24=\dfrac{25\pi-48}{2} . . . . ( 1 ) ....(1)

Now,

Area of 2 n d 2^{nd} largest semicircle = = Area of Yellow region + + Area of Green region = π R 2 2 = 16 π 2 . . . . . ( 2 ) =\dfrac{\pi\text{R}^2}{2}=\dfrac{16\pi}{2}.....(2)

Similarly,

Area of 3 r d 3^{rd} largest semicircle = = Area of Red region + + Area of Blue region = π R 2 2 = 9 π 2 . . . . . ( 3 ) =\dfrac{\pi\text{R}^2}{2}=\dfrac{9\pi}{2}.....(3)

Area of the lunar moons = ( 2 ) + ( 3 ) ( 1 ) = 16 π 2 + 9 π 2 25 π 48 2 = 25 π 2 25 π 48 2 = 48 2 = 24 =(2)+(3)-(1)=\dfrac{16\pi}{2}+\dfrac{9\pi}{2}-\dfrac{25\pi-48}{2}=\dfrac{25\pi}{2}-\dfrac{25\pi-48}{2}=\dfrac{48}{2}=\boxed{24}

Nice solution. Thank you for sharing it.

Hana Wehbi - 3 years, 3 months ago

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please upvote!

(haha)

Aaryan Maheshwari - 3 years, 3 months ago

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I did, usually l do that automatically, l am not sure how l forgot this time. I read your solution before having my coffee. By the end, l gave you my vote.

Hana Wehbi - 3 years, 3 months ago

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