Area of the green region

One green region is part of one sector of a circle. Therefore we need to find the area of one green region and multiply it by four.

Solve for the central angle.

$cos$ $∅ = \frac{2}{2.4}$

$∅ = 33.56$ ; $2∅ = 67.12$

Solve for the area of the triangle.

By Pythagorean Theorem, $x = \sqrt{2.4^2 - 2^2} = \sqrt{1.76}$ ; $2x = 2\sqrt{1.76}$

$A_{triangle} = \frac{1}{2}(2\sqrt{1.76})(2) = 2\sqrt{1.76}$

Solve for the area of the sector.

$A_{sector} = \frac{67.12}{360}π(2.4^2) = 3.37$

Solve for the area of the green region.

$A_{green} = 4(A_{sector} - A_{triangle}) = 4(3.37 - 2\sqrt{1.76}) = 3$ $square$ $meters$