Area of the yellow region - 2

Geometry Level 3

A regular decagon has side length of 5. Circular arcs of radius 2.5 are drawn at each vertex as shown. Find the area of the yellow region to the nearest integer. Use π = 3.1416 \pi=3.1416 .


The answer is 212.

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1 solution

The area of the yellow region is equal to the area of the regular decagon plus the sum of the areas of the five circular sectors outside the decagon minus the sum of the areas of the five circular sectors inside the decagon.

Area of the regular decagon:

By cosine law, we have

5 2 = 2 x 2 2 x 2 cos 36 5^2=2x^2-2x^2\cos 36 \implies 25 = x 2 ( 2 2 cos 36 ) 25=x^2(2-2\cos 36) \implies x 2 = 25 2 2 cos 36 x^2=\dfrac{25}{2-2\cos 36}

Area = 10 ( 1 2 ) ( x 2 ) ( sin 36 ) = 5 ( 25 2 2 cos 36 ) ( sin 36 ) 192.355 \text{Area} = 10\left(\dfrac{1}{2}\right)(x^2)(\sin 36)=5\left(\dfrac{25}{2-2\cos 36}\right)(\sin 36) \approx 192.355

Area of the five circular sectors outside the decagon:

Area = 5 ( 216 360 ) ( 3.1416 ) ( 2. 5 2 ) 58.905 \text{Area} = 5\left(\dfrac{216}{360}\right)(3.1416)(2.5^2)\approx 58.905

Area of the five circular sectors inside the decagon:

Area = 5 ( 144 360 ) ( 3.1416 ) ( 2. 5 2 ) 39.27 \text{Area} = 5\left(\dfrac{144}{360}\right)(3.1416)(2.5^2)\approx 39.27

Area of the yellow region:

Area of yellow region = 192.355 + 58.905 39.27 212 \text{Area of yellow region} = 192.355+58.905-39.27 \approx 212

Is this problem inspired by this ?

Micah Wood - 3 years, 6 months ago

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Yes, that was my old account actually. I am using a new account.

A Former Brilliant Member - 3 years, 6 months ago

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