Area of triangle

Geometry Level 3

Three sides of a triangle are 8 cm , 10 cm , 12 cm 8\text{ cm}, 10\text{ cm}, 12\text{ cm} . Find the area of this triangle.

512 cm 2 \sqrt{512 }\text{ cm}^2 1575 cm 2 \sqrt{1575}\text{ cm}^2 960 cm 2 \sqrt{960 }\text{ cm}^2 1245 cm 2 \sqrt{1245}\text{ cm}^2

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3 solutions

Use Heron’s Formula

s = 8 + 10 + 12 2 = 15 s=\dfrac{8+10+12}{2}=15

A = 15 ( 15 8 ) ( 15 10 ) ( 15 12 ) = 1575 A=\sqrt{15(15-8)(15-10)(15-12)}=\sqrt{1575}

Use the Heron's Formula:

s = a + b + c 2 = 8 + 10 + 12 2 = 15 s=\dfrac{a+b+c}{2}=\dfrac{8+10+12}{2}=15

A = s ( s a ) ( s b ) ( s c ) = 15 ( 15 8 ) ( 15 10 ) ( 15 12 ) = A=\sqrt{s(s-a)(s-b)(s-c)}=\sqrt{15(15-8)(15-10)(15-12)}= 1575 \boxed{\sqrt{1575}}

Aadit Sahoo
Dec 7, 2016

Its formula is first add the 3 sides and divide it by 2. then name the result as S. then to take out the area of triangle multiply S,S-1st side,S-2nd side and S-3rd side. so the solution of the problem is 8+10+12=30 30/2=15 ={15 (15-8) (15-10) (15-12)}cm^2 =(15 7 5 3)cm^2 =1575 cm^2

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