If a circular sector has an area that is numerically equal to the perimeter of its arc, what is its radius?
Note: The perimeter of the arc doesn't include the radius of the sector.
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It is quite simple to figure this out.
According to the question, area of the sector = perimeter of the arc.
The formula to find the area of the sector if the angle subtended by it is θ is,
3 6 0 θ π r 2 . . . . . . . . (i).
And, similarly for the perimeter of the arc, the formula is,
3 6 0 θ × 2 π r . . . . . . . . . .(ii).
Equating, (i) and (ii) we get,
3 6 0 θ π r 2 = 3 6 0 θ × 2 π r
Or, π r 2 = 2 π r
Or, r = 2