Area under the graph

Calculus Level 2

0 100 ( x x ) d x = ? \large \int_0^{100} (x-\lfloor x\rfloor)\ dx = ?

Notation: \lfloor \cdot \rfloor denotes the floor function .


The answer is 50.

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1 solution

Chew-Seong Cheong
May 30, 2018

I = 0 100 ( x x ) d x Note that x = x { x } = 0 100 { x } d x where 0 { x } < 1 is the fraction part of x . = 100 0 1 x d x = 100 x 2 2 0 1 = 50 \begin{aligned} I & = \int_0^{100} (x - {\color{#3D99F6}\lfloor x \rfloor})\ dx & \small \color{#3D99F6} \text{Note that }\lfloor x \rfloor = x - \{x\} \\ & = \int_0^{100} \{x\}\ dx & \small \color{#3D99F6} \text{where }0 \le \{x\} < 1 \text{ is the fraction part of }x. \\ & = 100 \int_0^1 x \ dx \\ & = 100 \cdot \frac {x^2}2 \bigg|_0^1 \\ & = \boxed{50} \end{aligned}

Perfect Solution!

Ayush G Rai - 3 years ago

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Glad that you like it.

You should use \lfloor x \rfloor for x \lfloor x \rfloor and call it floor function as in Brilliant.org instead of greatest integer function, which I believe is obsolete. I have amended the problem wording and LaTex codes for you.

You can see the LaTex codes by placing your mouse cursor on top of the formula or click the pull-down menu " \cdots More" below the answer section and select "Toggle LaTex".

Chew-Seong Cheong - 3 years ago

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oh..thank you so much.

Ayush G Rai - 3 years ago

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