Area Under This Curve

Algebra Level 3

Let the area enclosed by the graph of equation x + y = 1 |x| + |y| = 1 be A A . Find A + 100 A+100 .


The answer is 102.

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1 solution

The graph of x + y = 1 |x| + |y| = 1 is a square with vertices at ( 0 , 1 ) (0, 1) , ( 1 , 0 ) (1, 0) , ( 0 , 1 ) (0, -1) , and ( 1 , 0 ) (-1, 0) . Therefore, its side length is 1 2 + 1 2 = 2 \sqrt{1^2+1^2} = \sqrt2 and the area A = 2 2 = 2 A = \sqrt 2 \cdot \sqrt 2 = 2 , A + 100 = 102 \implies A + 100 = \boxed{102} .

Yup.....same!!

Aaghaz Mahajan - 3 years, 3 months ago

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