Let the area enclosed by the graph of equation be . Find .
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The graph of ∣ x ∣ + ∣ y ∣ = 1 is a square with vertices at ( 0 , 1 ) , ( 1 , 0 ) , ( 0 , − 1 ) , and ( − 1 , 0 ) . Therefore, its side length is 1 2 + 1 2 = 2 and the area A = 2 ⋅ 2 = 2 , ⟹ A + 1 0 0 = 1 0 2 .